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Find the discriminant and the number of real roots for this equation. x2 + 2x + 8 = 0
a.32; two real roots
b.–28; one real root
c.32; one real root
d.–28; no real roots

Respuesta :

Luv2Teach
Your discriminant is a negative number.  Therefore, your solutions are imaginary.  It's d from above.

Answer: Option 'D' is correct.

Step-by-step explanation:

Since we have given that

[tex]x^2+2x+8=0[/tex]

We will first find the "Discrimination":

[tex]D=b^2-4ac\\\\D=2^2-4\times 8\\\\D=4-32\\\\D=-28[/tex]

Since discriminant is less than 0 i.e. D<0.

So, there will no real roots.

Hence, D = -28 and there is no real roots.

Therefore, Option 'D' is correct.

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