bookboy2005
bookboy2005
30-05-2018
Mathematics
contestada
Cube root of - 1000p^12q^3
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jdoe0001
jdoe0001
30-05-2018
[tex]\bf \sqrt[3]{-1000p^{12}q^3}~~ \begin{cases} 1000=10^3\\ (-1)^3=-1\cdot -1\cdot -1\\ \qquad -1\\ p^{12}=p^{4\cdot 3}\\ \qquad (p^4)^3 \end{cases}\implies \sqrt[3]{(-1)^3(10)^3(p^4)^3q^3} \\\\\\ (-1)(10)p^4q\implies -10p^4q[/tex]
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