Respuesta :

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Answer

B) ㏒₁₂(1/2) - (㏒₁₂8 + ㏒₁₂W)

Explanation
The first law of logarithms is 
㏒AB = ㏒A+㏒B
㏒(A/B) = ㏒A - ㏒B
With this laws we can simplify the expression given

㏒₁₂((1/2)/8W) =㏒₁₂(1/2) - ㏒₁₂8W
                       = ㏒₁₂(1/2) - (㏒₁₂8 + ㏒W)