Syedsyed
Syedsyed
28-07-2018
Mathematics
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gmany
gmany
28-07-2018
[tex] \dfrac{4x^2+36}{4x}\cdot\dfrac{1}{5x}=\dfrac{4(x^2+9)}{4x\cdot5x}=\dfrac{x^2+9}{5x^2} [/tex]
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