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For f(x)=1/x^2-3
Find
A) f(3)
B) f(2-h)

Please show/explain how if you can .

For the function defined by the following attachment, evaluate f(0)

For fx1x23 Find A f3 B f2h Please showexplain how if you can For the function defined by the following attachment evaluate f0 class=

Respuesta :

altavistard

For f(x)=1/x^2-3

Find  

A) f(3)

B) f(2-h)

If f(x)=1/x^2-3, then f(3) = 1 / 3^2 - 3.  The exponentiation here must be carried out first:  f(3) = 1/9 - 3.  Then f(3) = 1/9 - 27/9 = -26/9

If f(x)=1/x^2-3, then f(2-h) = 1 / [2-h]^2 - 3.  This result may be left as is or expanded.  In expanded form, we have:

                     1

f(2-h) = ------------------ - 3

              4-4h +h^2