Here it is given that speed of the dog will increase from 5 m/s to 11 m/s in order to cover the distance of 22 m
so here we can use kinematics to find the acceleration
[tex]v_f = 11 m/s[/tex]
[tex]v_i = 5 m/s[/tex]
[tex]d = 22 m[/tex]
now we will have
[tex]v_f^2 - v_i^2 = 2 a d[/tex]
[tex]11^2 - 5^2 = 2(a)(22)[/tex]
[tex]a = \frac{11^2 - 5^2}{44}[/tex]
[tex]a = 2.18 m/s^2[/tex]
so here it will accelerate with a = 2.18 m/s^2
