Answer:
12.2 hours
Step-by-step explanation:
You want to find t such that y = 2·y₀. That is, you want to solve
... 2y₀ = y₀·e^(0.0567t)
Dividing by y₀, you have
... 2 = e^(0.0567t)
and taking the natural log gives ..
... ln(2) = 0.0567t
... ln(2)/0.0567 = t ≈ 12.2248 . . . . divide by the coefficient of t
The doubling time is approximately 12.2 hours.
