Answer: The sum of the first four integers is 200.
Step-by-step explanation:
Let x be the smallest odd integer, then the other seven integers will be [tex]x+2,x+4,x+6,x+8,x+10,+12\ and\ x+14[/tex]
The sum of the first four integers=[tex]x+(x+2)+(x+4)+(x+6)=4x+12[/tex]
The sum of the last four integers is 232.
[tex]\\\Rightarrow\ x+8+x+10+x+12+x+14=232\\\Rightarrow\ 4x+44=232\\\Rightarrow\ 4x=188\\\Rightarrow\ x=47[/tex]
Now, sum of the first four integers=[tex]4(47)+12=188+12=200[/tex]
