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Consider the reaction between no and cl2 to form nocl. 2no(g) + cl2(g) ⇌ 2nocl(g) a reaction mixture at a certain temperature initially contains only [no] = 0.50 m and [cl2] = 0.50 m. after the reaction comes to equilibrium, the concentration of nocl is 0.30 m. what is the value of kc at this temperature?

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superman1987

Answer:

1.125 x 10⁻³.

Explanation:

  • For the reaction: 2NO(g) + Cl₂(g) → 2NOCl(g).

Kc = [NOCl]²/[NO]²[Cl₂],

Where, [NOCl], [NO], and [Cl₂] is the equilibrium concentration of NOCl, NO, and Cl₂.

∵ Initial concentration of NO and Cl₂ = 0.50 M.

And the equilibrium concentration of NOCl = 0.30 M.

∴ The equilibrium concentration of NO, and Cl₂: [NO] = [Cl₂] = 0.50 M - 0.30 M = 0.20 M.

∴ Kc = [NOCl]²/[NO]²[Cl₂] = [0.30]²/[0.20]²[0.20] = 1.125 x 10⁻³.

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