WhiteWolfAsoka WhiteWolfAsoka

28-04-2016
Mathematics

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How do you integrate 7xe^-5x²?

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Аноним Аноним

28-04-2016

Making assumptions about where parentheses should be,
Let u = -7x
du = -7dx
dv = e^(2x) dx
v = e^(2x)/2
∫ -7xe^(2x) dx =
-7xe^(2x)/2 - ∫ e^(2x)/2 (-7) dx =
-7xe^(2x)/2 + 7e^(2x)/4 + c

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