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How much time would a force of 646 N need to stop a 82 kg object moving at 41 m/s (1 decimal place and no spaces between answer and units).

Respuesta :

Answer:

The time is 5.21 s.

Explanation:

Given that,

Force F = 646 N

Mass m = 82 kg

Velocity v = 41 m/s

We need to calculate the acceleration

Using formula of force

F= ma

[tex]a = \dfrac{F}{m}[/tex]

[tex]a = \dfrac{646}{82}[/tex]

[tex]a =7.87\ m/s^2[/tex]

We need to calculate the time

Now, using equation of motion

[tex]v = u+at[/tex]

[tex]41=0+7.87 t[/tex]

[tex]t = \dfrac{41}{7.87}[/tex]

[tex]t = 5.21\ s[/tex]

Hence, The time is 5.21 s.

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