Answer:
1.25×10⁻⁶ V
Explanation:
The expression for the calculation of the hall voltage is shown below:
[tex]V_{hall}=\frac {I (Current) \times B(Magnetic field)}{\rho (Density)\times Charge\times d(Thickness)}[/tex]
The charge of electron = 1.6×10⁻¹⁹ C
Given:
Density = 2.5×10²⁸ /m³
Thickness = 100 μm = 100×10⁻⁶ m = 10⁻⁴ m
B = 0.05 T
I = 10 A
[tex]V_{hall}=\frac {10 \times 0.05}{2.5\times 10^{28}\times 1.6\times 10^{-19}\times 10^{-4}}[/tex]
Hall Voltage = 1.25×10⁻⁶ V
