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A soccer player attempting to steal the ball from an opponent was extending her knee at 50 deg/s when her foot struck the opponent's shin pads. If the player's knee was stopped (0 deg/s) within 0.2 seconds, what angular acceleration did the knee experience?

Respuesta :

Answer:

[tex]\alpha = -4.36 rad/s^2[/tex]

Explanation:

Initial angular speed of the player is given as

[tex]\omega = 50 deg/s[/tex]

here we know that

[tex]1 deg = \frac{\pi}{180} rad[/tex]

now we know that

[tex]\omega = 50\frac{\pi}{180}[/tex]

[tex]\omega = 0.87 rad/s[/tex]

now its speed comes to zero in 0.2 s

so angular acceleration is given as

[tex]\alpha = \frac{\omega_f - \omega_i}{\Delta t}[/tex]

[tex]\alpha = \frac{0 - 0.87 rad/s}{0.2 s}[/tex]

[tex]\alpha = -4.36 rad/s^2[/tex]

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