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Mr. Harper's car used 5 gallons of gasoline to travel 150 miles. After he had some work done on the cars engine ,it used it used 6 gallons of gasoline to travel 210 miles. If the price of gasoline was $3.50 per gallon, how much money did Mr. Harper save per mile after the work was done on the cars engine? (Round your answers to the nearest cent.)

Respuesta :

Answer:

38.5 dollars

Step-by-step explanation:

Because if he used 3.50 dollars per a gallon that makes

6+5

=11

11*3.50

=35.5

maizetycorn

Answer:3.5$

Step-by-step explanation:r. First we have to let the car travel the same distance before and after the modification.Suppose 210 miles

Before:150/5=30mile/gallon   so we need 210/30=7gallons

After:210/6=35mile/gallon   so we need  210/35=6gallons

The difference is 1 gallon.1 multipy by  3.5$/gallon=3.5$

So 3.5$ is Mr.saved.

( I am not sure  if teh answer is correct.)

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