Answer:
-) (2-chloroethyl)cyclopropane
-) (1-chloroethyl)cyclopropane
-) 1-chloro-2-ethylcyclopropane
-) 1-chloro-1-ethylcyclopropane
Explanation:
The monochlorination are products in which Cl is added only 1 time. Now, in the ethylcyclopropane we will have 5 carbons, so we will have 5 options for monochlorination (see figure 1). But, for carbons 2 and 3 we will have equivalent structures, therefore at the end, we will have only 4 possible structures. In carbon 5, carbon 4, carbon 3 and carbon 1 (see figure 2).
