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The monomer seen below is called ethylene. Through addition polymerization it can be made into polyethylene, which goes by the abbreviation PE. Determine the degree of polymerization (DP) of a PE polymer with a molecular weight of 223300 g/mol.

Respuesta :

Answer:

The degree of polymerization, DP = 7961

Explanation:

Considering that:-

[tex]Mass_{Polymer}=n\times Mass_{Monomer}[/tex]

Where, n is the degree of polymerization (DP)

Thus, Given that monomer of this polymer is:- ethylene

Molar mass of monomer, ethylene = 28.05 g/mol

Given that, Molar mass of the polymer = 223300 g/mol

Thus,

[tex]223300=n\times 28.05[/tex]

[tex]n=\frac{406000}{51}[/tex]

[tex]n =7960.7843[/tex]

Thus, The degree of polymerization, DP = 7961

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