To solve this problem we will apply the linear motion kinematic equations, which describe the change in velocity, depending on the acceleration and the distance traveled, that is,
[tex]v_f^2 = v_i^2 +2ah[/tex]
Where,
[tex]v_f[/tex]= Final Velocity
[tex]v_i[/tex] = Initial Velocity
a = Acceleration
h = height
Our values are given as,
[tex]v_f = 88 ft/s\\v_i = 0 ft /s\\a = 32 ft/s^2\\[/tex]
Replacing we have,
[tex]vf^2 = vi^2 + 2*a*h[/tex]
[tex]88^2 = 0 + 2*32*h[/tex]
[tex]h= 121 ft[/tex]
Therefore the height of the cliff is 121ft
