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Calculate the Lattice Energy of KCl(s) given the following data using the Born-Haber cycle: ΔHsublimation K = 79.2 kJ/mol IE1 K = 418.7 kJ/mol Bond EnergyCl–Cl = 242.8 kJ/mol EACl = 348 kJ/mol ΔHKCl(s) = –435.7 kJ/mol

Respuesta :

Answer:

Explanation:

  The following equation relates to Born-Haber cycle

[tex]\triangle H_f = S + \frac{1}{2} B + IE_M - EA_X+ U_L[/tex]

Where

[tex]\triangle H_f[/tex] is enthalpy of formation

S is enthalpy of sublimation

B is bond enthalpy

[tex]IE_M[/tex] is ionisation enthalpy of metal

[tex]EA_X[/tex] is electron affinity of non metal atom

[tex]U_L[/tex] is lattice energy

Substituting the given values we have

-435.7 = 79.2 + 1/2 x 242.8 + 418.7 - 348 +U_L

[tex]U_L[/tex] = - 707 KJ / mol

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