Answer:
Both ball hit the ground about at the same time.
Explanation:
given information:
h = 2 m
the speed of red ball, v = 3 m/s
the time for red ball to reach the ground
h = [tex]\frac{1}{2}gt^{2}[/tex]
t = √2h/g
= √2(2)/9.8
= 0.64s
the time for yellow ball to reach the ground, it's considered as a vertical motion. thus
h = √2h/g
= √2(2)/9.8
= 0.64s
so, both ball hit the ground about at the same time.
