Answer:
Therefore, Δx=5/n, when have n intervals.
Step-by-step explanation:
From exercise we have interval [0,5]. So the length of the given interval is 5-0=5. Since all intervals [x0,x1],[x1,x2],…,[xn−1,xn] are equal in width.
We know that their width is Δx. We conclude that width of each subinterval Δx in terms of the number of subintervals n is equal 5/n.
Therefore, Δx=5/n, when have n intervals.
