Answer:
17.66 kPa
Explanation:
The volume of water in the swimming pool is the product of its dimensions
V = 30 * 8.7 * 1.8 = 469.8 cubic meters
Let water density [tex]\rho = 1000 kg/m^3[/tex], and g = 9.81 m/s2 we can calculate the total weight of water in the swimming pool
[tex]W = mg = \rho V g = 1000 * 469.8 * 9.81 = 4608738 N[/tex]
The area of the bottom
A = 30 * 8.7 = 261 square meters
Therefore the pressure is its force over unit area
[tex] P = F/A = 4608738 / 261 = 17658 N/m^2[/tex] or 17.66 kPa
