Answer:
24.09 grams of chlorine gas reacted.
Explanation:
[tex]2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)[/tex]
Moles of sodium chloride = [tex]\frac{39.7 g}{58.5 g/mol}=0.6786 mol[/tex]
According to reaction, 2 moles of NaCl are formed from 1 mole chlorine gas.
Then 0.6786 moles of NaCl will be formed from;
[tex]\frac{1}{2}\times 0.6786 mole=0.3393 mol[/tex]
Mass of 0.3393 moles of chlorine gas:
0.3393 mol × 71 g/mol = 24.09 g
24.09 grams of chlorine gas reacted.
