Answer:
2.16 × 10⁴ mg
Explanation:
A 14.0 wt% solution of CaCl₂ (110.98 g/mol) has a density of 1.126 g/mL. The density (ρ) of a solution is equal to the quotient between its mass (m) and its volume (V).
ρ = m/V
We can use this expression to find the mass of 19.2 mL of the 14.0 wt% solution of CaCl₂.
ρ = m/V
m = ρ × V
m = 1.126 g/mL × 19.2 mL
m = 21.6 g
1 gram is equal to 1000 milligrams. The milligrams corresponding to 21.6 grams are:
21.6 g × (1000 mg/1 g) = 2.16 × 10⁴ mg
