ShawnaMlangeni
ShawnaMlangeni
30-06-2016
Mathematics
contestada
-3y(-4y)=32+(x^0+y^0)^5
Respuesta :
toporc
toporc
30-06-2016
Any number to the power of 0 equals 1. So, we can rewrite the equation as follows:
[tex]12y=32+2^{5}=32+32=64[/tex]
[tex]y=\frac{64}{12}=5\frac{1}{3}[/tex]
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