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ABC trucking company realize that on an annual basis the distance traveled is normally distributed with a mean of 50,000 miles and a standard deviation of 12,000 miles using a normal distribution what is the probability that A randomly selected truck travels between 34,000 38000 miles

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Adematae

Answer:

0.7589

Explanation:

P(34000<=x<=38000)

P(34000-50000 / 12000) <= z <= 38000-50000 / 12000)

P( -16000/12000) <= z <= -12000/12000)

P(z<=-1.33)- p( z<=-1.00)

=0.9176 - 0.1587 (using standard normal table)

=0.7589

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