Answer:
0.029 Nm
Explanation:
We are given that
Length of wire,l=61 cm=[tex]\frac{61}{100}=0.61 m[/tex]
1 m=100 cm
Current,I=1 A
Magnetic field intensity,B=1 T
We have to find the maximum torque that can act on the loop.
[tex]r=\frac{l}{2\pi}=\frac{61}{2\times 3.14}=0.097 m[/tex]
Where [tex]\pi=3.14[/tex]
Torque,[tex]\tau=IAB=\pi r^2IB[/tex]
Substitute the values
[tex]\tau=3.14\times (0.097)^2\times 1\times 1=0.029 Nm[/tex]
