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Gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated NaOH ( aq ) . Calculate the amount of Ga ( s ) that can be deposited from a Ga ( III ) solution using a current of 0.710 A that flows for 70.0 min .

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Answer:

0.72g of gallium

Explanation:

Equation of the reduction reaction:

Ga^3+(aq) +3e --------> Ga(s)

If it takes 3F coulumbs of electricity to deposit 70g of gallium (relative atomic mass of gallium)

Then (0.710 × 70×60) coulombs of electricity will deposit (0.710 × 70×60) × 70/3F

But F = 96500C or 1Faraday

Therefore:

(0.710 × 70×60) × 70/3×96500

Mass of gallium deposited= 0.72g of gallium

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