Respuesta :

Answer:

[tex]\sqrt{8}=2\sqrt{2}[/tex]

Step-by-step explanation:

by using well known formula, distance on XOY plane

[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\=\sqrt{(-8-(-6))^2+(6-4)^2}

\\=\sqrt{(-2)^2+(2)^2}[/tex]