seemal
seemal
28-08-2016
Mathematics
contestada
Limit x approaches to 0 sinx/x°
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dalendrk
dalendrk
28-08-2016
[tex]\lim\limits_{x\to0}\dfrac{\sin x}{x}=\lim\limits_{x\to0}\dfrac{\cos x}{1}=\dfrac{1}{1}=1[/tex]
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