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(1) If y varies directly as x, and x = 3 and y = 9, solve for k

Write an equation that relates x & y


(2) If y varies inversely as x, and x = 3 and y = 12, Solve for k Write an equation that relates x & yIf y varies directly as x, and x = 3 and y = 9, solve for k

Write an equation that relates x & y


(3). If y varies inversely as x, and x = 3 and y = 12, Solve for k

Write an equation that relates x & y

Respuesta :

Answer:

[tex](1)y=\dfrac{1}{3}x\\\\(2)y=\dfrac{36}{x}[/tex]

Step-by-step explanation:

(1)

[tex]y \propto x\\y=kx\\$When x=3 and y=9\\9=3k; Therefore: $k=\frac{1}{3} \\$The equation that relates x and y is:$\\y=\dfrac{1}{3}x[/tex]

(2)

[tex]y \propto \frac{1}{x}\\y = \frac{k}{x}\\$When x=3 and y=12$\\12 = \frac{k}{3}; $Therefore: $k=3*12=36 \\$The equation that relates x and y is:$\\y=\dfrac{36}{x}[/tex]

Question 3 is a repetition of Question 2.

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