Using the inspection method,Which of the following is the constant term to use a numerator of the rational expression x2+8x+11x+6 have so (x + 6) is one of its factors?. .
For the numerator to have (x + 6) as a factor, its constant term must be____?
If ( x + 6 ) is a factor, then putting x = - 6 should make f ( x ) = 0: x² + 8 x + c ( - 6 )² + 8 * ( - 6 ) + c = 0 36 - 48 + c = 0 -12 + c = 0 c = 12 For the numerator to have ( x + 6 ) as a factor , its constant term must be 12 ( not 11 ).
