Answer:
= -13.6 eV
Explanation:
E = -13.6 ÷ [tex]\frac{Z^{2} }{n^{2} }[/tex]
where n is the principal state
Z is atomic number
and E is energy in electron volts.
Given that n = 2 and Helium Z = 2
⇒ E = -13.6 ÷ [tex]\frac{2^{2} }{2^{2} }[/tex]
= -13.6 eV
I believe this is helpful and easy to follow.
