Answer:
Density, [tex]\rho=0.49\ lb/in^3[/tex]
Explanation:
It is given that the density of liquid mercury is 13.6 g/mL. We need to convert the density into lb/in³.
We know that,
2.205 lbs= 1 kg
1 g = 0.0022 lb
1 mL = 0.0610 in³
[tex]13.6\ \dfrac{g}{mL}=13.6\times \dfrac{0.0022\ lb}{0.0610\ in^3}\\\\=0.49\ lb/in^3[/tex]
So, the density of liquid mercury is [tex]0.49\ lb/in^3[/tex].
