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11. A bicycle with an initial velocity of +6 m/s accelerates at a rate of +2 m/s2 for 3
seconds. What distance does the bicycle travel during this time?
C С
18 m
9 m
27 m
36 m

Respuesta :

ujalakhan18

Answer:

[tex]\huge\boxed{\sf S = 27 m}[/tex]

Explanation:

Given:

Initial Velocity = [tex]\sf V_{i}[/tex] = 6 m/s

Acceleration = a = 2 m/s²

Time = t = 3 secs

Required:

Distance = S = ?

Formula:

[tex]\sf S = V_{i}t + \frac{1}{2} at^2[/tex]         (Second Equation of Motion)

Solution:

S = (6)(3) + 1/2 (2)(3)²

S = 18 + 9

S = 27 m

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AnonymousHelper1807

Answer:

S=27 m

Explanation:

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