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15. A photoelectron experiment is performed on a sample of silicon using photons with an energy


of 1.43 x 105 kJ/mole. Photoelectrons are generated that have a kinetic energy of 1.34 x 10


kJ/mole. What was the ionization energy of these electrons?

Respuesta :

abidemiokin

Answer:

9.0×10^3K/moles

Step-by-step explanation:

ionization energy of these electrons = Energy of photons - kinetic energy of the electrons

Given

Kinetic energy of electron = 1.34×10^5

Energy of photons = 1.43 x 105 kJ/mole

Required

Ionization energy of these electrons

Ionization energy of these electrons = 1.43×10^5-1.34×10^5

ionization energy of these electrons = 0.09×10^5 kJ/mol

= 9.0 × 10^3 kJ/mol

Hence the ionization energy of these electrons is 9.0×10^3K/moles

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