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What is the magnetic force on a proton that is moving at 3.8 x 10^7 m/s up through a magnetic field that is 0.72 T and pointing toward you?

Respuesta :

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The force is F = B q v = 0.72 x 1.6x 10^-19 x 3.8 x 10 ^7 = .... N
The force will be at 90 degrees to both the motion of the proton and the magnetic field.

Answer:

4.4 x 10^-12 N right

Explanation:

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