Answer:
V2 = 0.98mL
Explanation:
Using Charles' law equation which I as follows:
V1/T1 = V2/T2
Where;
V1 = initial volume (mL)
T1 = initial temperature (K)
V2 = final volume (mL)
T2 = final temperature (K)
Based on the information provided in this question; V1 = 0.80 mL, V2 = ?, T1 = 23°C, T2 = 88°C
Temperature in °C must be converted to Kelvin
T1 (K) = 23°C + 273 = 296K
T2 (K) = 88°C + 273 = 361K
Hence, using V1/T1 = V2/T2
0.80/296 = V2/361
296 × V2 = 0.80 × 361
296V2 = 288.8
V2 = 288.8/296
V2 = 0.9756
V2 = 0.98mL
