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A car drives straight down toward the bottom of a valley and up the other side on a road whose bottom has a radius of curvature of 115m. At the very bottom, the normal force on the driver is twice his weight. At what speed was the car traveling?

Respuesta :

Answer:33.58794 m/s

Explanation : fCenrtipetal force = mv2/r

m = Mass of car

r = Radius of curvature = 115 m

g = Acceleration due to gravity = 9.81 m/s²

The normal force is given by

N=Fc+mg

At the bottom N = 2N

2mg=fc+mg

⇒2mg=mv2

The car was traveling at the speed of 33.58794 m/s

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