Answer:
Work done = 664.69 J
Explanation:
Given data:
Work done = ?
Initial volume = 13.43 L
Final volume = 6.87 L
Pressure = 1.91 atm
Solution:
work done = W = -PΔV
ΔV = V₂- V₁
work done = w = -P(V₂- V₁)
Now we will put the values in formula.
W = - 1 atm (6.87 L - 13.43 L)
W = - 1 atm (-6.56 L)
W = 6.56 atm.L
atm.L to joule:
6.56 atm.L × 101.325 J / 1L.atm
664.69 J
