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Question 3 of 10
An engine performs 6400 J of work on a motorbike. The motorbike and rider
have a combined mass of 200 kg. If the bike started at rest, what is the speed
of the bike after the work is performed?

Respuesta :

Answer:

8 m/s

Explanation:

KE Formula: KE = 1/2mv^2

Kinetic Energy is equal to energy, J.

6400 = 1/2 * 200 * V^2

1/2 * 200 = 100

6400 = 100 * V^2

6400/100 =  V^2

64 = V^2

Square root both sides

Speed is  8 m/s

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