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How much NaCl would you dissolve and dilute to the 100.00 mL mark in a volumetric flask with DI H2O to prepare a 0.825 M sodium chloride solution?

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Answer:

4.82 g

Explanation:

To solve this problem we'll use the definition of molarity:

  • Molarity = moles / liters

We are given the volume and concentration (keep in mind that 100mL=0.100L):

  • 0.825 M = moles / 0.100 L

Now we calculate the number of NaCl moles required:

  • moles = 0.0825 mol

Then we convert 0.0825 NaCl moles into grams, using its molar mass:

  • 0.0825 mol * 58.44 g/mol = 4.82 g

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