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Starting from rest, this airliner accelerates at 2.4m/s2 for 32 seconds before leaving the ground. Calculate its velocity at liftoff.

Respuesta :

Answer:

The velocity will be "76.8 m/s".

Explanation:

The given values are:

Acceleration,

a = 2.4 m/s²

Time,

t = 32 seconds

By equation of motion,

⇒  [tex]v=u+at[/tex]

On substituting the values, we get

⇒     [tex]=0+2.4\times 32[/tex]

⇒     [tex]=0+76.8[/tex]

⇒     [tex]=76.8 \ m/s[/tex]