Answer:
a = 1.67 m/s²
Explanation:
Given that,
Initial speed, u = 0
Final speed, v = 20 m/s
Time, t = 12 s
We need to find the distance traveled using the equation, d = 1/2 at².
Where
a is acceleration, a = (v-u)/t,
[tex]a=\dfrac{20-0}{12}=1.67\ m/s^2[/tex]
So,
[tex]d=\dfrac{1}{2}\times \dfrac{v-u}{t}\times t^2\\\\d=\dfrac{1}{2}\times {v-u}\times t\\\\d=\dfrac{1}{2}\times {20-0}\times 12\\\\d=10\ m[/tex]
Hence, the acceleration is 1.67 m/s² and the distance traveled is 10m.
