Answer:
The correct solution is "[tex]8.012\times 10^{13} \ per/sec[/tex]".
Explanation:
Given:
Power,
P = 1.00 W
Time,
t = 1 sec
Average energy,
E₀ = 78.0 KeV
Or,
= [tex]78.0\times 10^3\times 1.6\times 10^{-19}[/tex]
= [tex]124.8\times 10^{-16} \ J[/tex]
As we know,
⇒ [tex]Power =\frac{Total \ energy}{Time}[/tex]
or,
⇒ [tex]P=\frac{nE_0}{t}[/tex]
⇒ [tex]1.00=\frac{n(124.8\times 10^{-16})}{1}[/tex]
⇒ [tex]n=8.012\times 10^{13} \ per/sec[/tex]
