Respuesta :

Answer:

Step-by-step explanation:

[tex]f(x)=-2x+4\\g(x)=2x^2-2x-8\\(g\circ f)(x)=g(f(x))\\=g(-2x+4)\\=2(-2x+4)^2-2(-2x+4)-8\\=2(4x^2-16x+16)+4x-8-8\\=8x^2+(-32x+4x)+(32-8-8)\\=8x^2-28x+16[/tex]

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