mt1iful6Kaylor mt1iful6Kaylor

29-12-2016
Mathematics

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Suppose $81^x = 64$. what is $27^{x 1}$?

Respuesta :

maddymarostica maddymarostica

29-12-2016

x ln 81 = ln 64

x = ln 64/ln 81
x+1 = (ln 64 +ln 81)/ln 81

27^((ln 64+ln 81)/ln 81)
and simplify hope this helps!

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