Respuesta :

remember
(ab)/(cd)=(a/c)(b/d)
also
a²-b²=(a-b)(a+b)

so

(8(x-1)²)/(6(x²-1))=
(8/6)((x-1)²)/(x²-1)=
(4/3)((x-1)(x-1))/((x-1)(x+1))=
(4/3)((x-1)/(x+1))=
(4(x-1))/(3(x+1))=
(4x-4)/(3x+3)