Respuesta :

[tex]\huge\mathfrak{Solution :- }[/tex]

★ Molecular weight of Calcium carbonate (CaCO)

=> 40+12+(16×3)

=> 100 g

Given,

Weight : 25g

Therefore,

Number of Moles

[tex] = > \frac{Weight}{Molecular \:mass}[/tex]

[tex] = > \frac{25}{100} [/tex]

[tex] = > 0.25 \: moles[/tex]

★Hence, O.25 moles of calcium carbonate used.

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