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004 (part 1 of 3) 10.0 points

Two moles of helium gas initially at 410 K
and 0.47 atm are compressed isothermally to
1.34 atm.
Find the final volume of the gas. Assume
that helium behaves as an ideal gas. The
universal gas constant is 8.31451 J/K · mol.

005 (part 2 of 3) 10.0 points
Find the work done by the gas.
Answer in units of kJ.


006 (part 3 of 3) 10.0 points
Find the thermal energy transferred.
Answer in units of kJ.

Respuesta :

okpalawalter8

The final volume of the gas, work done, and the thermal energy transferred  is mathematically given as

vf=0,0623m^2

W=-4.03KJ

Q=-4.03KJ

What are the final volume of the gas, work done, and the thermal energy transferred?

Generally, the equation for the ideal gas   is mathematically given as

Pv=nRT

Therefore

vf=nRT/P

vf=2*8.314330/1*1.01*10^3

vf=0,0623m^2

In conclusion

vi=nRT/Pi

vi=0.1175m^3

w=pdv

w=2*8.314*330in()0.0623/0.117

W=-4.03KJ

Where

Q=W

Q=-4.03KJ

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