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A ball is dropped from rest from the top of a high building. Ignore air resistance and take g = 9,8 m/s² calculate speed of the ball after 1sec.
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Respuesta :

pstnonsonjoku

The speed of the ball after one second is obtained as 9.8 m/s.

What is the speed after 1 second?

We know that  since the ball dropped from a height, its initial velocity is zero.

Thus we have;

u = 0 m/s

v = ???

g =  9,8 m/s²

t =  1sec

Given that;

v = u + at

v = at

v =  9,8 m/s² *  1sec

v = 9.8 m/s

Learn more about acceleration:https://brainly.com/question/12550364?

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